Inserting returns for each space
Not sure if I am doing something wrong, but I have a string
Sometimes there are leading or trailing spaces so I trim it
But I also want to insert a carriage return for each space
However, when I use the following script, it always displays
it as follows in the respective portal....
Substitute ( TrimAll ( $Variable; 1 ; 0 ) ; " " ; ¶ )
So lets's say my variable is " Jack Jill Sam Tom"
My $variable is still "Jack Jill Sam Tom"
I want it to be....
I use a setField command to place the above value
Thanks for any help
Perhaps the character between each word is not the space character and thus does not get a return substituted for it. There are a number of other non-visible characters that will look like space but aren't.