AnsweredAssumed Answered

Choose Function - use $variable for result

Question asked by fmdataweb on Sep 18, 2017
Latest reply on Sep 18, 2017 by fmdataweb

I'm trying to use a variable for the result part of the Choose function. For example instead of using:

 

Choose ( Rating ; "Not Applicable" ; "Good" ; "Fair" ; "Poor" )

 

I would like to use:

 

Choose ( Rating ; $results )

 

where $results is a variable containing:

 

"Not Applicable" ; "Good" ; "Fair" ; "Poor"

 

I haven't been able to get this to work so far - is it possible to use a variable for the results part of the Choose function, or do you have to hard coded this all the time?

Outcomes