Rent ≤ 450 and # 8 ft tables ≥ 2 and # 6 ft tables ≥ 1 ; 35 ;
Rent ≤ 450 and # 8 ft tables>1 and # 6 ft tables>1 ;35 ;
Rent ≤ 450 and # 6 ft tables > 2 ; 35
A standard booth (rent = $450 or less) comes with two tables (either 8 ft or 6 ft). Our pipe & drape company charges an extra $35 fee for any additional tables. Most dealers choose two 8 ft tables, and my database (written by a previous manager) is written to handle this scenario. There are times, however, that a dealer chooses to substitute two 6 ft tables for 8 ft tables, and that should not result in any fees (it currently does). Other times, a dealer will choose to substitute one 6 ft table for an 8 ft table, but also opt for an additional 6 ft table. In that case, I need to charge the $35 extra table fee. In fact, in any scenario that results in a dealer requiring more than two tables, they need to be charged a fee. I wrote the above formula hoping to accomplish this automatically, but it isn't working. Can someone please advise what it is that I am doing wrong? I am really struggling and appreciate any assistance!